Akbar's journal

Kamis, 30 Juli 2015

That fluffy marsupial

Hwehehehe, i've just saw a nice pic of a marsupial animal
Called quokka...
uuhhhh, it's cute!
Fluffy, and fatty
and, it's the happiest animal in the world...
Emm, many people want to have it, as a pet
but, huh, you simply can't...
It was threatened, well, at least it's counted as vulnerable, you can still found it in the wild
You can found it in Australia, especially around Southwest, Rottsnest island,bald island, and albany

Well, want to know something, well, it's science
Ok, let's talk about taxonomy, here the taxonomy chart

Kingdom : Animalia
Phylum : Chordata
Class : Mammalia
Order : Diprotodontia
Family : Macropodidae
Subfamily : Macropodinae
Genus : Setonix (It's the only animal with 'setonix' Genus)
Binominal/Scientific name : Setonix Brachyurus
Common name : Quokka

whether you want to call it quokka, or other name, it's still cute, and adorable!
Remember what i mention you earlier?, about it's habitat?
it's usually live around dense vegetation that close to water (usually close to the beach)
It has brown, dark red, or gray fur
And, it's photogenic!

Well, if you want to look for a quokka there, dont forget to bring a plant that classified as Guichenotia, they like it!

And,uhh, how sad, it's now classified as 'Vulnerable'
It's threatened in the Australian mainland, threatened by the Dog, Fox, Dingo, and Cat
Well, it's still not threatened too much in other offshore island, it's safe there

And, maybe its time to go
I post this in my class....
bye!
xoxo

Selasa, 28 Juli 2015

Trying to make this blog a little bit useful...

uhh, it's been a long time since the last time i post something
and, uhh
Maybe, i'm gonna post something useful in this blog :D
Uh, maybe a couple o' article or writing shit i make

Umm, let's start with...
Sedna's closest encounter on sun, is 76 AU away from sun
1 AU is same with the lenght between the sun and earth
and, it's Aphelion (Farthest encounter) is 936 AU away from the earth
I will give you some wikipedia refference here!

Umm, maybe i need to go now, i'm updating this blog at school, and i need to go home
Bye!

Kamis, 23 Juli 2015

Well....

Well...
i just want to tell you something
My friend ask me to review her story
What can i say, there's some grammatical error there, and else

and i need to go now :v
bye!
xoxo!

Selasa, 21 Juli 2015

Just want to say goodbye...

Ok, i made this post, to say goodbye...
Just like what i've told you yesterday, i cant update this blog, routine
Well, the phone i usually use, get bootlooped, and i cant fix it

Ok, let me tell you what happen today, Bag of cholestrol, an import book, travel, and a lot of shoes
Ok, i eat some fast food, travel, bought new book and shoes...
that's it

Ok, i often think about her again, emm, you know...
And, i've got a new idea, i must continue my deserted work
Mainland
The main idea of Project Surabaya, but with a slightly different plot

Well, wanna say goodbye now
hope can see you soon...
bye
xoxo

Senin, 20 Juli 2015

De-Routine

Ok, i want to tell you something
I cant post something routine now...
Maybe for a couple o' days, weeks, months, name it all

What happen?
The thing that actually happen is my mom cellphone is, for an unknown reason, broken
for an unknown reason, it gets bootlooped....
I've try to reset it, take out the battery, and, nothing happen, it just get bootlooped
Maybe its a medium or hard bootloop

Well, maybe i need too go
With this, i want to tell you, goodbye
Hope can see you soon, whoever you are
xoxo

Jumat, 17 Juli 2015

First day

Ok, it's the first ied fitr day, it's friday, and i ate a lot this day
Well, i want to tell you some stories

Well, at the morning, i just wake up and do what shall i do in the morning
And then wait till' 10 am, wait till first group of my big family member
Well, the next is not too important
And, we pass all the event till 12, after friday pray
Me, and my family come to the other family member house
And, the road is...
What can i say, quiet, almost empty
There's only a few car around me

And i love that kind of situation
Make me want to write the first project again

Ok, skip all of that things till nite, when i play KSP
And, other family member come
At 19.30 (i think)
And, well, nothing special, to be honest, i just spend the whole time reading about kuiper belt, TNO's, and oort cloud
Well, i've just being a nerd again

Ok, i need to go, need some rest, tomorrow, i gonna go somewhere with my bike or playing KSP
Bye!
xoxo (nobody tell me why xoxo mean kiss and hug, so, i search it for myself and found the answer)

Kamis, 16 Juli 2015

Ied Mubarak All!

Well, it's 20.54 at night, and 16/07/2015
And, it's the last day of ramadhan!
*uraaa
Well, tomorow, there will be many foods here, in my house, and when i'm bored with the food here
I can go to my neighbour or other family member house, and eat!
And, there is a possibility to be a rich person tomorow

Ok, it's a little bit loud right here, and when i ask one of my friend, she said, it's loud too there
the sounds of firework, firecracker, and other stuff (Including takbir) are here, i'm afraid that one of of that sounds around me is a military class explosion (?)
Well, if you want some kind of artilery battle feeling, you can wait till' the new year, and come to the nearest firework party, but , dont get too close, get a little bit far (500m maybe work), and look for a quiet place, wait till 00.00, and feel it

Ok, i'm talking too much shit now
I need to continue my kerbal space program rocket
Well, if you think, kerbal space program is only an ordinary game, i'll proof you are wrong
I will tell you how to orbit

First, you need to adjust your orbiting speed
The relation between orbital speed and acceleration is given by the formula:

a={\frac {v^{2}}{r}},

where a is the acceleration due to gravity, v is the horizontal speed, and r is the radius of orbit.
Of course, gravity varies depending on your distance from the planet, so we also need the following formula to determine a based on your altitude:

a=g\left({\frac {R}{R+h}}\right)^{2},

where g is the acceleration due to gravity at sea level (9.807 m/s²), R is the radius of Kerbin (600 km), and h is the altitude of your orbit.
Note: Since the radius of your orbit r is equal to the radius of Kerbin R plus your altitude h, we can substitute R + h for r.
Now we have two expressions for a, so we set them on opposite sides of an equation and simplify:

{\begin{aligned}g\left({\frac {R}{(R+h)}}\right)^{2}&={\frac {v^{2}}{r}}\\g\left({\frac {R}{(R+h)}}\right)^{2}&={\frac {v^{2}}{R+h}}\\g{\frac {R^{2}}{(R+h)^{2}}}&={\frac {v^{2}}{R+h}}\\g{\frac {R^{2}}{R+h}}&=v^{2}\\v^{2}&=g{\frac {R^{2}}{R+h}}\\v&={\sqrt {g{\frac {R^{2}}{R+h}}}}\\v&=R{\sqrt {{\frac {g}{R+h}}}}\\\end{aligned}}

Finally, substituting known values for g and R,

v=600\ 000\ {\mathrm {m}}{\sqrt {{\frac {9.807\ {\mathrm {m}}/{\mathrm {s}}^{2}}{600\ 000\ {\mathrm {m}}+h}}}}

And then, the orbital period
From the basic mechanics formula:

d=vt

We know v from the above, and d is simply the circumference of a circle with a radius equal to your orbital altitude plus the radius of Kerbin:

t=2\pi {\frac {600\ 000\ {\mathrm {m}}+h}{v}}

And, last but not least, orbital equation
For this section it is assumed that the craft in question is orbiting a particular body and is a lot smaller than the body that it is orbiting. Other then in the general orbital equation and the energy equation, the orbits are assumed to be bounded orbits completely within the body's sphere of influence and no others. This section also assumes that classical physics applies in the game. All distances and radii are from the center of the body being orbited and the sea level radius of the body needs to be added to the altitude given in game to recover the values here. The section uses the standard gravitational parameter

\mu =GM

which

G

is Newton's Gravitational Constant and

M

is the mass of the body that is being orbited. From here on out

m

will refer to the mass of the craft.
When the craft is orbiting a body, the distance between the craft and the body is given by the equation

r(\phi )={\frac {l^{2}}{\mu m^{2}}}{\frac {1}{1+\epsilon cos\phi }}

where

l

is the angular momentum of the craft,

\epsilon

is the eccentricity of the orbit, and

\phi

is an angle parameter for the orbit.

\phi

runs from

0\deg

360\deg

l=m\cdot r\cdot v

at apoapsis or periapsis, and

\epsilon \geq 0

. When

\epsilon <1

the orbit is bounded and is an ellipse and when

\epsilon \geq 1

the orbit is unbounded. At

\phi =0\deg

the craft is at the periapsis and at

\phi =180\deg

the craft is at the apoapsis. At periapsis,

r_{p}={\frac {l^{2}}{\mu m^{2}}}{\frac {1}{1+\epsilon }}

and at apoapsis,

r_{a}={\frac {l^{2}}{\mu m^{2}}}{\frac {1}{1-\epsilon }}

.
The semimajor axis is

a={\frac {l^{2}}{\mu m^{2}}}{\frac {1}{1-\epsilon ^{2}}}

and the semiminor axis is

b={\frac {l^{2}}{\mu m^{2}}}{\frac {1}{{\sqrt {1-\epsilon ^{2}}}}}

\epsilon ={\frac {{\sqrt {a^{2}-b^{2}}}}{a}}

Given the results for

r_{p}

and

r_{a}

above,

l^{2}=2\mu m^{2}{\frac {r_{p}r_{a}}{r_{p}+r_{a}}}

and

\epsilon ={\frac {r_{a}-r_{p}}{r_{p}+r_{a}}}

thus

r(\phi )=2{\frac {r_{p}r_{a}}{r_{p}+r_{a}+(r_{a}-r_{p})cos\phi }}

The velocity for an object in elliptical orbit about a much larger object is

v={\sqrt {\mu ({\frac {2}{r}}-{\frac {1}{a}})}}={\sqrt {\mu {\frac {r_{p}^{2}+r_{a}^{2}+(r_{a}^{2}-r_{p}^{2})cos\phi }{r_{p}r_{a}(r_{p}+r_{a})}}}}={\sqrt {2\mu {\frac {r_{p}+r_{a}-r}{r(r_{p}+r_{a})}}}}

.
The energy for an object in orbit is

E={\frac {\mu ^{2}m^{3}}{2l^{2}}}(\epsilon ^{2}-1)={\frac {\mu m(r_{p}+r_{a})}{4r_{p}r_{a}}}(\epsilon ^{2}-1)=-{\frac {\mu m}{r_{p}+r_{a}}}

.
One should note that for bounded orbits, the energy is negative and for escape orbits, energy is non-negative.
The orbital period is

\tau ={\sqrt {{\frac {4\pi ^{2}}{\mu }}a^{3}}}={\sqrt {{\frac {\pi ^{2}(r_{p}+r_{a})^{3}}{2\mu }}}}

.
Let

r_{{c,1}}

and

r_{{o,1}}

be the two apsides of a given orbit and let a craft execute a burn imparting a specific

\Delta v

all at the single point in time the craft is at

r_{{c,1}}

. For this problem

\Delta v

can be either positive or negative. If it is positive then the thrust is to speed up the craft but if it is negative the ture delta v is the oppositie of that in the problem but the thrust is to slow down the craft. This problem assumes that the thust is in the same or opposite direction of travel and is not enough to reverse the craft. The new orbit will have apsides of

r_{{c,2}}

and

r_{{o,2}}

with

r_{{c,2}}=r_{{c,1}}

.
The speed of the craft before the burn is

v_{1}={\sqrt {2\mu {\frac {r_{{c,1}}+r_{{o,1}}-r_{{c,1}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,1}})}}}}={\sqrt {2\mu {\frac {r_{{o,1}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,1}})}}}}

.
The speed of the craft after the burn is

v_{2}=v_{1}+\Delta v={\sqrt {2\mu {\frac {r_{{c,2}}+r_{{o,2}}-r_{{c,2}}}{r_{{c,2}}(r_{{c,2}}+r_{{c,2}})}}}}={\sqrt {2\mu {\frac {r_{{o,2}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,2}})}}}}={\sqrt {2\mu {\frac {r_{{o,1}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,1}})}}}}+\Delta v

which yields

\Delta v={\sqrt {{\frac {2\mu }{r_{{c,1}}}}}}({\sqrt {{\frac {r_{{o,2}}}{r_{{c,1}}+r_{{o,2}}}}}}-{\sqrt {{\frac {r_{{o,1}}}{r_{{c,1}}+r_{{o,1}}}}}})

and

r_{{o,2}}=r_{{c,1}}{\frac {r_{{c,1}}({\sqrt {2\mu {\frac {r_{{o,1}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,1}})}}}}+\Delta v)^{2}}{2\mu -r_{{c,1}}({\sqrt {2\mu {\frac {r_{{o,1}}}{r_{{c,1}}(r_{{c,1}}+r_{{o,1}})}}}}+\Delta v)^{2}}}=r_{{c,1}}{\frac {r_{{c,1}}v_{2}^{2}}{2\mu -r_{{c,1}}v_{2}^{2}}}

Well, still thinking that game give you nothing?
Think again

Well, i want to go now
continue build some rocket
Bye!
xoxo (well, is there anyone know why "xoxo" means hug and kiss?)

Ps. Again, Ied Mubarak All!